A) \[(2,-1)\]
B) \[[-2,1]\]
C) R
D) \[(-1,1)\]
E) \[(-2,\text{ }0)\]
Correct Answer: B
Solution :
Let \[y={{\sin }^{-1}}\left( \frac{2x+1}{3} \right)\] \[\therefore \] \[-1\le \frac{2x+1}{3}\le 1\] \[(\because -1\le {{\sin }^{-1}}x\le 1)\] \[\Rightarrow \] \[-3\le 2x+1\le 3\] \[\Rightarrow \] \[-4\le 2x\le 2\] \[\Rightarrow \] \[-2\le x\le 1\] \[\therefore \] \[x\in [-2,1]\]You need to login to perform this action.
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