A) 2
B) \[\frac{3}{4}\]
C) \[3\]
D) \[\frac{1}{4}\]
E) \[\frac{1}{2}\]
Correct Answer: B
Solution :
\[\because \]\[\alpha \]and\[\beta \]are the roots of\[4{{x}^{2}}+2x-1=0,\] then\[\alpha +\beta =-\frac{1}{2},\alpha \beta =-\frac{1}{4}\] \[\therefore \] \[{{\alpha }^{2}}+{{\beta }^{2}}={{(\alpha +\beta )}^{2}}-2\alpha \beta \] \[=\frac{1}{4}+\frac{2}{4}=\frac{3}{4}\]You need to login to perform this action.
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