A) 320 K
B) 100 K
C) zero
D) 273 K
E) 400 K
Correct Answer: A
Solution :
\[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\Rightarrow \frac{8000}{6400}=\frac{400}{{{T}_{2}}}\] \[\Rightarrow \] \[{{T}_{2}}=320\,K\]
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