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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    A solid disc of mass M is just held in air horizontally by throwing 40 stones per second vertically upwards to strike the disc each with a velocity\[6\text{ }m{{s}^{-1}}\]. If the mass of each stone is 0.05 kg, what is the mass of the disc? \[(g=10\text{ }m{{s}^{-2}})\]

    A)  1.2 kg         

    B)  0.5 kg  

    C)         20 kg                                    

    D)  3 kg

    E)  4kg

    Correct Answer: A

    Solution :

    Balance condition is weight of disc = upward force due to 40 stones \[\Rightarrow \] \[M\times 10=40\times 0.05\times 6\] \[\Rightarrow \] \[M=1.2kg\]


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