A) \[{{Y}_{B}}=2{{Y}_{A}}\]
B) \[{{Y}_{A}}={{Y}_{B}}\]
C) \[{{Y}_{B}}=3{{Y}_{A}}\]
D) \[{{Y}_{A}}=3{{Y}_{B}}\]
E) \[{{Y}_{B}}=\frac{1}{3}{{Y}_{A}}\]
Correct Answer: D
Solution :
\[Y=\frac{stress}{strain}=\]slope of the graph\[=\tan \theta \] \[\therefore \] \[\frac{{{Y}_{A}}}{{{Y}_{B}}}=\frac{\tan 60{}^\circ }{\tan 30{}^\circ }=\frac{\sqrt{3}}{1/\sqrt{3}}=3\] \[\Rightarrow \] \[{{Y}_{A}}=3{{Y}_{B}}\]
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