CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The orbital speed of an artificial satellite very close to the surface of the earth is\[{{v}_{o}}\]. Then the orbital speed of another artificial satellite at a height equal to the three times the radius of the earth is:

    A)  \[4\,{{v}_{o}}\]                               

    B)  \[2\,{{v}_{o}}\]               

    C)  \[0.5\,{{v}_{o}}\]           

    D)         \[{{v}_{o}}\]

    E)  \[2/3\,{{v}_{o}}\]

    Correct Answer: C

    Solution :

    \[{{v}_{o}}=\sqrt{\frac{GM}{R}}\] \[v_{o}^{}=\sqrt{\frac{GM}{R+3R}}=\sqrt{\frac{GM}{4R}}\] \[\Rightarrow \]               \[v_{o}^{}=\frac{1}{2}{{v}_{o}}=0.5\,{{v}_{o}}\]


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