A) \[{{F}_{1}}=2{{F}_{2}}\]
B) \[{{F}_{2}}=2{{F}_{1}}\]
C) \[{{F}_{1}}={{F}_{2}}\]
D) \[{{F}_{1}}=-{{F}_{2}}\]
E) \[{{F}_{2}}=4{{F}_{1}}\]
Correct Answer: D
Solution :
\[{{F}_{BA}}=\frac{{{\mu }_{0}}{{I}^{2}}}{2\pi x}\](attractive force) and\[{{F}_{CA}}=\frac{{{\mu }_{0}}(I)(2I)}{2\pi (2x)}=\frac{{{\mu }_{0}}{{I}^{2}}}{2\pi x}\]repulsive force) Hence, \[{{F}_{BA}}=-{{F}_{CA}}\Rightarrow {{F}_{1}}=-{{F}_{2}}\]You need to login to perform this action.
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