CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    A truck of mass 30000 kg moves up an inclined plane of slope 1 in 100 at speed of 30 km/h. The power of the truck is (given \[g=10\text{ }m{{s}^{-1}}\]):

    A)  25 kW                                  

    B)  10 kW  

    C)         5 kW                    

    D)         2.5 kW

    E)  0.5 kW

    Correct Answer: A

    Solution :

    \[{{F}_{net}}=30000\times 10\times \frac{1}{100}=3\times {{10}^{3}}N\] \[\therefore \] \[P=F.v=3\times {{10}^{3}}\times 30\times \frac{5}{18}=25\,kW\]


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