A) \[B{{F}_{3}}>N{{F}_{3}}>N{{H}_{3}}\]
B) \[N{{F}_{3}}>B{{F}_{3}}>N{{H}_{3}}\]
C) \[N{{H}_{3}}>B{{F}_{3}}>N{{F}_{3}}\]
D) \[N{{H}_{3}}>N{{F}_{3}}>B{{F}_{3}}\]
E) \[N{{H}_{3}}=N{{F}_{3}}>B{{F}_{3}}\]
Correct Answer: D
Solution :
Dipole moment of\[N{{F}_{3}}\]is less than\[N{{H}_{3}}\]and the dipole moment of\[B{{F}_{3}}\]is always zero. So, the correct arrangement of molecules on the basis of their dipole moment is: \[N{{H}_{3}}>N{{F}_{3}}>B{{F}_{3}}\]
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