A) co-ordination isomers
B) linkage isomers
C) ionization isomers
D) hydrate isomers
E) optical isomers
Correct Answer: C
Solution :
\[[PtC{{l}_{2}}{{(N{{H}_{3}})}_{4}}]B{{r}_{2}}\]and\[[PtB{{r}_{2}}{{(N{{H}_{3}})}_{4}}]C{{l}_{2}}\]shows ionization isomerism because in ionization isomerism the difference arises from the position of groups within or outside the co-ordination sphere. Therefore, these isomers give different ions in the solution.
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