A) 156
B) 145
C) 150
D) 108
E) 48
Correct Answer: A
Solution :
\[P_{A}^{o}=120\,mm,P_{B}^{o}=180\,mm\] Number of moles of A and B = 2 moles and 3 moles respectively. Total pressure of solution \[={{P}_{A}}+{{P}_{B}}\] \[P=P_{A}^{o}{{x}_{A}}+P_{B}^{o}{{x}_{B}}\] ...(i) where,\[x{}^\circ \]mole fraction, \[\left( \frac{n}{n+N} \right)\] \[x_{A}^{o}=\frac{2}{2+3}=\frac{2}{5}=0.4\] \[x_{B}^{o}=\frac{2}{2+3}=\frac{3}{5}=0.6\] On putting the values of \[x_{A}^{o},x_{B}^{o},p_{A}^{o}\]and\[p_{B}^{o}\]in Eq. (i) \[=120\times 0.4+180\times 0.6\] \[=48.0+108.0\] \[=156.0\text{ }mm\]
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