A) 1 and\[2-i\]
B) -1 and\[3+i\]
C) 0 and 1
D) -1 and\[i-2\]
E) none of these
Correct Answer: A
Solution :
\[\because \]One root of\[{{x}^{3}}-5{{x}^{2}}+9x-5=0\]is\[2+i,\]then another root will be\[2-i,\] Let\[\alpha \]be third root of given equation. \[\therefore \]\[2+i+2-i+a=5\Rightarrow \alpha =1\]You need to login to perform this action.
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