CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    If the n th term of the geometric progression, \[5,-\frac{5}{2},\frac{5}{4},\frac{5}{8},....\]is\[\frac{5}{1024},\]then the value of n is:

    A)  11                                         

    B)                         10

    C)                         9                                            

    D)                         4

    E)                         7

    Correct Answer: A

    Solution :

    \[\because \] \[5{{\left( -\frac{1}{2} \right)}^{n-1}}=\frac{5}{1024}\] \[\Rightarrow \]               \[{{\left( -\frac{1}{2} \right)}^{n-1}}={{\left( -\frac{1}{2} \right)}^{10}}\] \[\Rightarrow \]               \[n-1=10\] \[\Rightarrow \]               \[n=11\]


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