A) 1
B) \[-1\]
C) i
D) \[-i\]
E) 0
Correct Answer: E
Solution :
\[i+{{i}^{2}}+{{i}^{3}}+...\]upto 1000 terms \[=\frac{i(1-{{i}^{1000}})}{1-i}=\frac{i(1-1)}{1-i}\] \[=\frac{i}{1-i}\times 0=0\]
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