CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The least integer k which makes the roots of the equation\[{{x}^{2}}+5x+k=0\]imaginary, is:

    A)  4                                            

    B)                         5

    C)                         3                                            

    D)                         7

    E)                         8

    Correct Answer: C

    Solution :

    \[\because \]The roots of given equation are imaginary, then Discriminant, \[25-4{{k}^{2}}<0\] \[\Rightarrow \]               \[{{k}^{2}}>\frac{25}{4}\] \[\Rightarrow \]               \[k>\frac{5}{2}\] \[\therefore \]Least value of\[k=3\].


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