A) 50/7 unit
B) 50/3 unit
C) 25/3 unit
D) 25/4 unit
E) 3/50 unit
Correct Answer: B
Solution :
\[\therefore \]\[\overrightarrow{F}=\frac{5(2\hat{i}-2\hat{j}+\hat{k})}{\sqrt{4+4+1}}=\frac{5}{3}(2\hat{i}-2\hat{j}+\hat{k})\] and \[\overrightarrow{d}=(5\hat{i}+3\hat{j}+7\hat{k})-(\hat{i}+2j+3\hat{k})\] \[=4\hat{i}+\hat{j}+4\hat{k}\] \[\therefore \] \[W=\overrightarrow{F}.\overrightarrow{d}=\frac{5}{3}(2\hat{i}-2\hat{j}+\hat{k})\] \[(4\hat{i}+\hat{j}+4\hat{k})\] \[=\frac{5}{3}(8-2+4)=\frac{50}{3}unit\]
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