CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    An unit vector perpendicular to both\[\hat{i}+\hat{j}\] and \[\hat{j}+\hat{k}\] is:

    A)  \[\hat{i}-\hat{j}+\hat{k}\]                          

    B)                         \[\hat{i}+\hat{j}+\hat{k}\]

    C)                         \[\frac{\hat{i}+\hat{j}-\hat{k}}{\sqrt{3}}\]                          

    D)                         \[\frac{\hat{i}-\hat{j}+\hat{k}}{\sqrt{3}}\]

    E)                         none of these

    Correct Answer: D

    Solution :

    \[\because \]\[(\hat{i}+\hat{j})\times (\hat{j}+\hat{k})\] \[=\left| \begin{matrix}    {\hat{i}} & {\hat{j}} & {\hat{k}}  \\    1 & 1 & 0  \\    0 & 1 & 1  \\ \end{matrix} \right|\] \[=\hat{i}-\hat{j}+\hat{k}\] and\[|(\hat{i}+\hat{j})\times (\hat{j}+\hat{k})|=\sqrt{1+1+1}=\sqrt{3}\] \[\therefore \]Unit vector perpendicular to both\[\hat{i}+\hat{j}\]and\[\hat{j}+\hat{k}\]                 \[=\frac{(\hat{i}+\hat{j})\times (\hat{j}+\hat{k})}{|(\hat{i}+\hat{j})\times (\hat{j}+\hat{k})|}\]                 \[=\frac{\hat{i}-\hat{j}+\hat{k}}{\sqrt{3}}\]


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