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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The equation of the plane passing through (2, 3, 4) and parallel to the plane \[5x-6y+7z=3\]is:

    A) \[5x-6y+7z+20=0\]

    B)                         \[5x-6y+7z-20=0\]

    C)                         \[5x+6y-7z+3=0\]

    D)                         \[5x+6y+7z+3=0\]

    E)                         \[5x+6y+7z-3=0\]

    Correct Answer: B

    Solution :

    Equation of plane parallel to given plane is \[5x-6y+7z=\lambda \] \[\because \]It passes through (2, 3, 4) \[\therefore \] \[\lambda =10-18+28=20\] \[\therefore \]Required equation is \[5x-6y+7z-20=0\]


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