CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A body of mass 2 kg makes an elastic collision with another body at rest and continues to move in the original direction with one-fourth its original speed. The mass of the second body which collides with the first body is:

    A)  2 kg                                      

    B)  1.2 kg  

    C)         3 kg                      

    D)         1.5 kg

    E)  1 kg

    Correct Answer: B

    Solution :

    Conservation of linear momentum gives \[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}\] \[\Rightarrow \]               \[{{m}_{2}}{{v}_{2}}=\frac{3u}{2}\]                          ?? (1) Conservation of kinetic energy gives \[\frac{1}{2}{{m}_{1}}u_{1}^{2}+\frac{1}{2}{{m}_{2}}u_{2}^{2}=\frac{1}{2}{{m}_{1}}v_{1}^{2}+\frac{1}{2}{{m}_{2}}v_{2}^{2}\] \[\Rightarrow \]               \[{{m}_{2}}v_{2}^{2}=\frac{15{{u}^{2}}}{8}\]                                   ...(2) Hence, on solving Eqs. (1) and (2), we get \[{{m}_{2}}=1.2\,kg\]


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