A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{2}\]
C) \[\frac{2\pi }{3}\]
D) \[-\frac{2\pi }{3}\]
E) 0
Correct Answer: A
Solution :
\[\theta ={{\sin }^{-1}}\{-\sin 600{}^\circ \}={{\sin }^{-1}}\{-\sin 240{}^\circ \}\] \[={{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right)\] \[\Rightarrow \] \[\theta =60{}^\circ =\frac{\pi }{3}\]You need to login to perform this action.
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