A) \[{{x}^{2}}-4x-8y-12=0\]
B) \[{{x}^{2}}-4x+8y+12=0\]
C) \[{{x}^{2}}+8y=12\]
D) \[{{x}^{2}}-4x+12=0\]
E) none of the above
Correct Answer: B
Solution :
Let co-ordinate of directrix in which meet the axis at Z is \[(\alpha ,\beta )\] \[\therefore \] \[\frac{\alpha +2}{2}=2\]\[\Rightarrow \]\[\alpha =2\] and \[\frac{\alpha -3}{2}=-1\Rightarrow \beta =1\] \[\therefore \]Co-ordinate of Z is (2, 1). \[\therefore \]equation of directrix is\[y=1\] \[\therefore \] \[PS=PM\] \[\Rightarrow \] \[{{(x-2)}^{2}}+{{(y+3)}^{2}}={{(y-1)}^{2}}\] \[\Rightarrow \] \[{{x}^{2}}-4x+8y+12=0\]You need to login to perform this action.
You will be redirected in
3 sec