A) \[xyz\]
B) 0
C) 1
D) \[2xyz\]
E) \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}\]
Correct Answer: A
Solution :
\[{{\tan }^{-1}}x+{{\tan }^{-1}}y+{{\tan }^{-1}}z=\pi \] \[\Rightarrow \] \[{{\tan }^{-1}}\left\{ \frac{x+y+z-xyz}{1-xy-yz-zx} \right\}=\pi \] \[\Rightarrow \] \[x+y+z-xyz=0\] \[\Rightarrow \] \[x+y+z=xyz\]You need to login to perform this action.
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