question_answer

If the angle of elevation of the top of a tower at a distance 500 m from its foot is 30°, then the height of the tower is:

A)  \[\frac{1}{\sqrt{3}}m\]                

B)         \[500\sqrt{3}m\]

C)         \[\sqrt{3}m\]                   

D)         \[\frac{1}{500}m\]

E)         \[\frac{500}{\sqrt{3}}m\]

Correct Answer: E

Solution :

In \[\Delta ABC,\] \[\therefore \]  \[\tan 30{}^\circ =\frac{h}{500}\] \[\Rightarrow \]               \[h=\frac{500}{\sqrt{3}}m\]