A) 110
B) 191
C) 80
D) 194
E) 195
Correct Answer: D
Solution :
We have \[tan\text{ }A+cot\text{ }A=4\] On squaring both sides, we get \[ta{{n}^{2}}A+co{{t}^{2}}A+2=16\] \[\Rightarrow \] \[ta{{n}^{2}}A+co{{t}^{2}}A=16-2=14\] Again squaring, we get \[ta{{n}^{4}}A+co{{t}^{4}}A+2=196\] \[\Rightarrow \] \[ta{{n}^{4}}A+co{{t}^{4}}A=196-2=194\]You need to login to perform this action.
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