CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    If\[\theta ={{\sin }^{-1}}[\sin (-600{}^\circ )],\]then one of the possible values of\[\theta \]is:

    A)  \[\frac{\pi }{3}\]                                             

    B)         \[\frac{\pi }{2}\]

    C)         \[\frac{2\pi }{3}\]                                           

    D)         \[-\frac{2\pi }{3}\]

    E)         0

    Correct Answer: A

    Solution :

    \[\theta ={{\sin }^{-1}}\{-\sin 600{}^\circ \}={{\sin }^{-1}}\{-\sin 240{}^\circ \}\] \[={{\sin }^{-1}}\left( \frac{\sqrt{3}}{2} \right)\] \[\Rightarrow \]               \[\theta =60{}^\circ =\frac{\pi }{3}\]


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