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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The eccentricity of the conic\[9{{x}^{2}}+25{{y}^{2}}=225\] is:

    A)  \[\frac{2}{5}\]  

    B)                                         \[\frac{4}{5}\]

    C)         \[\frac{1}{3}\]                                  

    D)         \[\frac{1}{5}\]

    E)         \[\frac{3}{5}\]

    Correct Answer: B

    Solution :

    The given equation is \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{9}=1\] The eccentricity, \[e=\sqrt{1-\frac{9}{25}}\]                                 \[=\sqrt{\frac{16}{25}}\]                                 \[=\frac{4}{5}\]


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