A) \[6\,\Omega \]
B) \[4\,\Omega \]
C) \[2.9\,\Omega \]
D) \[3.1\,\Omega \]
E) \[2.5\,\Omega \]
Correct Answer: C
Solution :
\[I=\frac{E-e}{R}\] ...(1) and \[\eta \times 100=\left( \frac{e}{E} \right)\times 100\] ...(2) \[\therefore \] \[30=\frac{e}{50}\times 100\] (from Eqs. (2)) \[\Rightarrow \] \[e=15V\] Thus, \[R=\frac{50-15}{12}=2.9\,\Omega \]You need to login to perform this action.
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