CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    Two circuits have mutual inductance of 0.1 H. What average emf is induced in one circuit when the current in the other circuit changes from 0 to 20 A in 0.02 s?

    A)  240 V                   

    B)         230 V   

    C)  100 V                   

    D)         300 V

    E)  200 V

    Correct Answer: C

    Solution :

    \[e=M\times \frac{dI}{dt}\] \[=0.1\times \frac{(20-0)}{0.02}=100\,V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner