A) rhombic S
B) prismatic S (colloidal)
C) amorphous S
D) monoclinic S
E) plastic S
Correct Answer: B
Solution :
When\[{{H}_{2}}S\]gas is passed through nitric acid, colloidal sulphur is formed as. \[{{H}_{2}}\overset{-2}{\mathop{S}}\,+\overset{+5}{\mathop{2HN{{O}_{3}}}}\,\xrightarrow{{}}2{{H}_{2}}O+\overset{+4}{\mathop{2N{{O}_{2}}}}\,+\overset{0}{\mathop{S}}\,\]You need to login to perform this action.
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