CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    The rms speed of the molecules of a gas in a vessel is\[400\text{ }m{{s}^{-1}}\]. If half of the gas leaks out, at constant temperature, the rms speed of the remaining molecules will be:

    A)  \[800\,m{{s}^{-1}}\]                                      

    B)  \[400\sqrt{2}\,m{{s}^{-1}}\]      

    C)         \[400\,m{{s}^{-1}}\]                      

    D)  \[200\,m{{s}^{-1}}\]

    E)  \[200\sqrt{2}\,m{{s}^{-1}}\]

    Correct Answer: C

    Solution :

    \[{{v}_{rms}}\propto \sqrt{T}\] Hence, rms speed remains\[400\text{ }m{{s}^{-1}}\].


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