2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2002

  • question_answer
    A steel scale is to be prepared such that the millimetre intervals are to be accurate within\[6\times {{10}^{-5}}mm\]. The maximum temperature variation during the ruling of the millimeter marks is\[(a=12\times {{10}^{-6}}/{}^\circ C)\]:

    A)  \[4.0{}^\circ C\]              

    B) \[4.5{}^\circ C\]

    C)         \[5.0{}^\circ C\]           

    D)        \[3{}^\circ C\]

    E)  \[5.5{}^\circ C\]

    Correct Answer: C

    Solution :

    \[\alpha =\frac{\Delta L}{L\times \Delta t}\Rightarrow 12\times {{10}^{-6}}=\frac{6\times {{10}^{-5}}}{1\times \Delta t}\] \[\Rightarrow \]               \[\Delta t=\frac{6\times {{10}^{-5}}}{12\times {{10}^{-6}}}=\frac{60}{12}=5{}^\circ C\]


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