A) \[8\,h\]
B) \[6\,h\]
C) \[4\,h\]
D) \[2\,h\]
E) \[1\,h\]
Correct Answer: B
Solution :
\[L={{I}_{1}}{{\omega }_{1}}={{I}_{2}}{{\omega }_{2}}\] \[\Rightarrow \] \[\frac{2}{5}M{{R}^{2}}\times \frac{2\pi }{{{T}_{1}}}=\frac{2}{5}M{{\left( \frac{R}{2} \right)}^{2}}\times \frac{2\pi }{{{T}_{2}}}\] \[\Rightarrow \] \[{{T}_{2}}=\frac{{{T}_{1}}}{4}=\frac{24}{4}=6\,h\]You need to login to perform this action.
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