A) 1 and 64
B) 4 and 16
C) 2 and 16
D) 8 and 16
E) 3 and 16
Correct Answer: B
Solution :
Let the GP series be\[1,{{G}_{1}},{{G}_{2}},64\] Here,\[a=1,\text{ }n=4,\text{ }l=64\] \[\therefore \] \[64={{(r)}^{3}}\] \[\Rightarrow \] \[r=4\] \[\therefore \] \[{{G}_{1}}=4\]and \[{{G}_{2}}={{1.4}^{2}}=16\]You need to login to perform this action.
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