A) forms water only
B) acts as an oxidizing agent
C) acts as a reducing agent
D) reduces sulphuric acid
E) produces hydrogen
Correct Answer: C
Solution :
The reaction of\[{{H}_{2}}{{\text{O}}_{2}}\]with\[KMn{{O}_{4}}\]and\[{{H}_{2}}S{{O}_{4}}\]is as follows: \[\overset{+7}{\mathop{2KMn{{O}_{4}}}}\,+3{{H}_{2}}S{{O}_{4}}+5{{H}_{2}}{{O}_{2}}\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}\] \[+\overset{+2}{\mathop{2MnS{{O}_{4}}}}\,+8{{H}_{2}}O+\overset{0}{\mathop{5{{O}_{2}}}}\,\] Here,\[{{H}_{2}}{{O}_{2}}\]acts as a reducing agent and it reduced to\[KMn{{O}_{4}}\]to\[M{{n}^{2+}}\]ion.
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