A) 1
B) 2
C) 5
D) 4
E) 3
Correct Answer: E
Solution :
\[\because \]Centre and radius of circle\[{{x}^{2}}+{{y}^{2}}=4\]are \[{{C}_{1}}(0,0)\]and 2 respectively and centre and radius of circle\[{{x}^{2}}+{{y}^{2}}-8x+12=0\]are \[{{C}_{2}}(4,0)\]and \[2\]respectively. \[\because \]Here, \[{{C}_{1}}{{C}_{2}}={{r}_{1}}+{{r}_{2}}\] \[\therefore \]Circles touch each other externally so the number of common tangents is 3.You need to login to perform this action.
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