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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    The equation to the sides of a triangle are \[x-3y=0,\text{ }4x+3y=5\]and\[3x+y=0\]. The line \[3x-4y=0\]passes through:

    A)  the incentre    

    B)         the centroid

    C)  the orthocentre

    D)         the circumcentre

    E)  none of these

    Correct Answer: C

    Solution :

    Two sides\[x-3y=0\]and\[3x+y=0\]are perpendicular to each other. Therefore its orthocentre is the point of intersection of \[x-3y=0\]and\[3x+y=0\]i. e., (0, 0). Clearly (0, 0) satisfies\[3x-4y=0\].


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