CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    The equation of the parabola with vertex at the origin and directrix\[y=2\]is:

    A)  \[{{y}^{2}}=8x\]                              

    B)  \[{{y}^{2}}=-8x\]            

    C)         \[{{y}^{2}}=\sqrt{8}x\]     

    D)         \[{{x}^{2}}=8y\]

    E)  \[{{x}^{2}}=-8y\]

    Correct Answer: E

    Solution :

    \[\because \]Directrix of parabola is\[y=2.\] \[\therefore \]  \[a=-2\] \[\therefore \]Required equation of parabola is                 \[{{x}^{2}}=-4.2.y\] \[\Rightarrow \]               \[{{x}^{2}}=-8y\]


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