A) \[-3\]
B) 3
C) 0
D) for any value of b
E) for no value of b
Correct Answer: D
Solution :
The matrix\[\left[ \begin{matrix} 5 & 10 & 3 \\ -2 & -4 & 6 \\ -1 & -2 & b \\ \end{matrix} \right]\]is singular, if \[\left| \begin{matrix} 5 & 10 & 3 \\ -2 & -4 & 6 \\ -1 & -2 & b \\ \end{matrix} \right|=0\] \[\Rightarrow \]\[-1(60+12)+2(30+6)\] \[+b(-20+20)=0\] \[\Rightarrow \] \[-72+72+0b=0\] The given matrix is singular for any value of b.You need to login to perform this action.
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