A) \[{{e}^{-\log x}}+c\]
B) \[-x{{e}^{-\log x}}+c\]
C) \[{{e}^{\log x}}+c\]
D) \[\log x+c\]
E) \[\log |x|+c\]
Correct Answer: E
Solution :
\[\int{{{e}^{-\log x}}}dx\] \[=\int{{{e}^{\log 1/x}}}dx=\int{\frac{1}{x}}dx\] \[=\log |x|+c\]You need to login to perform this action.
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