A) \[f(x)\]
B) \[\frac{1}{f(x)}\]
C) \[-f(x)\]
D) \[-\frac{1}{f(x)}\]
E) not defined
Correct Answer: A
Solution :
Let \[y=f(x)=\frac{1-x}{1+x}\] \[\Rightarrow \] \[y+yx=1-x\] \[\Rightarrow \] \[1-y=x(1+y)\] \[\Rightarrow \] \[x=\frac{1-y}{1+y}\] \[\therefore \] \[{{f}^{-1}}(x)=\frac{1-x}{1+x}=f(x)\]You need to login to perform this action.
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