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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    If a focal chord of the parabola\[{{y}^{2}}=ax\]is \[2x-y-8=0,\]then the equation of the directrix is:

    A)  \[x+4=0\]       

    B)         \[x-4=0\]           

    C)         \[y-4=0\]       

    D)         \[y+4=0\]

    E)  none of these

    Correct Answer: A

    Solution :

    \[\because \]Focal chord of parabola\[{{y}^{2}}=ax\]is \[2x-y-8=0\] \[\because \]This chord passes through focus\[\left( \frac{a}{4},0 \right)\] \[\therefore \]  \[2.\frac{a}{4}-0-8=0\] \[\Rightarrow \]               \[a=16\] \[\therefore \]Directrix is\[x=-4\] \[\Rightarrow \]               \[x+4=0\]


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