2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    A man weighs 80 kg on earth surface. The height above ground where he will weigh 40 kg, is: (radius of earth is 6400 km)

    A)  0.31 times r

    B)         0.41 times r       

    C)         0.51 times r    

    D)         0.61 times r

    E)  0.82 times r

    Correct Answer: B

    Solution :

    \[w=\frac{w}{{{\left( 1+\frac{h}{r} \right)}^{2}}}\] \[\Rightarrow \]               \[40=\frac{80}{{{\left( 1+\frac{h}{r} \right)}^{2}}}\] \[\Rightarrow \]               \[h=0.41\,r\]


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