A) 0
B) 4
C) \[-4\]
D) 8
E) none of these
Correct Answer: A
Solution :
\[\because \] \[f(x)=2{{x}^{2}}-4x+1\] \[\therefore \] \[g(x)=\frac{2{{x}^{2}}-4x+1-2{{x}^{2}}-4x-1}{2}\] \[\Rightarrow \] \[g(x)=-4x\] \[\therefore \] \[\int_{-3}^{3}{g(x)}dx=-4\int_{-3}^{3}{x}\,dx\] \[=-4{{\left[ \frac{{{x}^{2}}}{2} \right]}^{3}}\] \[=-2[9-9]=0\]You need to login to perform this action.
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