A) 35
B) 48
C) 60
D) 22
E) 30
Correct Answer: C
Solution :
\[n(M)=100,n(p)=70,n(C)=40\] \[n(M\cap P)=30,n(M\cap C)=28,\] \[n(P\cap C)=23,\]and\[n(M\cap P\cap C)=18\] \[\therefore \]\[n(M\cap P\cap C)=n[M\cap (P\cap C)]\] \[=n(M)-n[M\cap (P\cup C)]\] \[=n(M)-[n(M\cap P)+n(M\cap C)\] \[-n(M\cap P\cap C)]\] \[=100-[30+28-18]\] \[=60\]You need to login to perform this action.
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