A) \[{{x}^{2}}\]
B) \[{{x}^{2}}-1\]
C) \[{{x}^{2}}-2\]
D) \[{{x}^{2}}+1\]
E) \[{{x}^{2}}+2\]
Correct Answer: C
Solution :
\[f\left( x+\frac{1}{x} \right)={{x}^{2}}+\frac{1}{{{x}^{2}}}={{\left( x+\frac{1}{x} \right)}^{2}}-2\] \[\therefore \] \[f(x)={{x}^{2}}-2\]You need to login to perform this action.
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