A) \[1:1\]
B) \[1:2\]
C) \[2:1\]
D) \[1:8\]
E) \[8:1\]
Correct Answer: E
Solution :
\[{{B}_{axis}}=\frac{{{\mu }_{0}}ni{{R}^{2}}}{2{{({{R}^{2}}+{{x}^{2}})}^{3/2}}}\] \[{{B}_{centre}}=\frac{{{\mu }_{0}}ni}{2R}\] At\[x=\sqrt{3}R,\]\[{{B}_{axis}}=\frac{{{\mu }_{0}}ni{{R}^{2}}}{2{{({{R}^{2}}+3{{R}^{2}})}^{3/2}}}\] \[=\frac{{{\mu }_{0}}ni}{16R}\] \[\therefore \] \[\frac{{{B}_{centre}}}{{{B}_{axis}}}=\frac{8}{1}\]
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