CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    The force on a conductor of length\[l\]placed in a magnetic field of magnitude B and carrying a current I is given by (\[\theta \]is the angle, the conductor makes with the direction of B):

    A)  \[F=I\,l\,B\sin \theta \]

    B)         \[F={{I}^{2}}\,l\,{{B}^{2}}\sin \theta \] 

    C)  \[F=I\,l\,B\cos \theta \]

    D)                         \[F=\frac{{{I}^{2}}l}{B}\sin \theta \]

    E)  \[F=\frac{{{I}^{2}}l}{B}\cos \theta \]

    Correct Answer: A

    Solution :

    Not available


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