• # question_answer A beaker containing a liquid appears to be half when it is actually two third full. The refractive index of liquid is: A)  7/6                       B)         6/5                       C)  3/2                       D)         5/4E)  4/3

Solution :

$\mu =\frac{\frac{2}{3}h}{\frac{1}{2}h}=\frac{4}{3}$ h being depth of beaker.

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