A) \[[{{h}^{1}}{{c}^{1}}{{G}^{-1}}]\]
B) \[[{{h}^{1/2}}{{c}^{1/2}}{{G}^{-1/2}}]\]
C) \[[{{h}^{1}}{{c}^{-3}}{{G}^{1}}]\]
D) \[[{{h}^{1/2}}{{c}^{-3/2}}{{G}^{1/2}}]\]
E)
Correct Answer: D
Solution :
Let \[L=[{{h}^{a}}{{c}^{b}}{{G}^{d}}]\] \[\therefore \]\[[{{L}^{}}]={{[M{{L}^{2}}{{T}^{-1}}]}^{a}}{{[L{{T}^{-1}}]}^{b}}{{[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]}^{c}}\] \[\Rightarrow \] \[a=\frac{1}{2},b=-\frac{3}{2},d=\frac{1}{2}\] Hence, \[L=[{{h}^{1/2}}{{c}^{-3/2}}{{G}^{1/2}}]\]You need to login to perform this action.
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