A) exactly at the target
B) 10 cm below the target
C) 10 cm above the target
D) 5 cm below the target
E) 5 cm above the target
Correct Answer: E
Solution :
\[s=ut\] \[\Rightarrow \] \[t=\frac{s}{u}=\frac{50}{500}=0.1s\] \[\therefore \] \[h=0+\frac{1}{2}g{{t}^{2}}\] \[=\frac{1}{2}\times 10\times {{(0.1)}^{2}}\] \[=0.05\text{ }m=5\text{ }cm\] (above the target)You need to login to perform this action.
You will be redirected in
3 sec